源代码： Lib/fnmatch.py
此模块提供对 Unix Shell 样式通配符的支持，这 not 与正则表达式相同 (文档化在 re 模块)。用于 Shell 样式通配符的特殊字符：
| 模式 | 含义 |
|---|---|
| * | 匹配一切 |
| ? | 匹配任何单字符 |
| [seq] | 匹配任何字符在 seq |
| [!seq] | 匹配任何字符不在 seq |
对于文字匹配，将元字符包裹在括号中。例如， '[?]' 匹配字符 '?' .
Note that the filename separator ( '/' on Unix) is not special to this module. See module glob for pathname expansion ( glob 使用 fnmatch() to match pathname segments). Similarly, filenames starting with a period are not special for this module, and are matched by the * and ? patterns.
Test whether the filename string matches the pattern string, returning True or False . If the operating system is case-insensitive, then both parameters will be normalized to all lower- or upper-case before the comparison is performed. fnmatchcase() can be used to perform a case-sensitive comparison, regardless of whether that’s standard for the operating system.
This example will print all file names in the current directory with the extension .txt :
import fnmatch import os for file in os.listdir('.'): if fnmatch.fnmatch(file, '*.txt'): print file
测试是否 filename 匹配 pattern ，返回 True or False ; the comparison is case-sensitive.
Return the subset of the list of 名称 that match pattern . It is the same as [n for n in 名称 if fnmatch(n, pattern)] , but implemented more efficiently.
2.2 版新增。
Return the shell-style pattern converted to a regular expression.
范例：
>>> import fnmatch, re >>> >>> regex = fnmatch.translate('*.txt') >>> regex '.*\\.txt$' >>> reobj = re.compile(regex) >>> reobj.match('foobar.txt') <_sre.SRE_Match object at 0x...>
另请参阅
